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12k^2+82k=-60
We move all terms to the left:
12k^2+82k-(-60)=0
We add all the numbers together, and all the variables
12k^2+82k+60=0
a = 12; b = 82; c = +60;
Δ = b2-4ac
Δ = 822-4·12·60
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-62}{2*12}=\frac{-144}{24} =-6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+62}{2*12}=\frac{-20}{24} =-5/6 $
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